class: title-slide # 2.3 — Cost Minimization ## ECON 306 • Microeconomic Analysis • Fall 2022 ### Ryan Safner<br> Associate Professor of Economics <br> <a href="mailto:safner@hood.edu"><i class="fa fa-paper-plane fa-fw"></i>safner@hood.edu</a> <br> <a href="https://github.com/ryansafner/microF22"><i class="fa fa-github fa-fw"></i>ryansafner/microF22</a><br> <a href="https://microF22.classes.ryansafner.com"> <i class="fa fa-globe fa-fw"></i>microF22.classes.ryansafner.com</a><br> --- # Recall: The Firm's Two Problems .pull-left[ .smallest[ 1<sup>st</sup> Stage: .hi[firm's profit maximization problem]: 1. **Choose:** .hi-blue[ < output >] 2. **In order to maximize:** .hi-green[< profits >] - We'll cover this later...first we'll explore: 2<sup>nd</sup> Stage: .hi[firm's cost minimization problem]: 1. **Choose:** .hi-blue[ < inputs >] 2. **In order to _minimize_:** .hi-green[< cost >] 3. **Subject to:** .hi-red[< producing the optimal output >] - Minimizing costs `\(\iff\)` maximizing profits ] ] .pull-right[ .center[ ![](../images/management.jpg) ] ] --- class: inverse, center, middle # Solving the Cost Minimization Problem --- # The Firm's Cost Minimization Problem .pull-left[ - The **firm's cost minimization problem** is: 1. **Choose:** .blue[ < inputs: `\\(l, k\\)`>] 2. **In order to minimize:** .green[< total cost: `\\(wl+rk\\)` >] 3. **Subject to:** .red[< producing the optimal output: `\\(q^*=f(l,k)\\)` >] ] .pull-right[ .center[ ![](../images/management.jpg) ] ] --- # The Cost Minimization Problem: Tools .pull-left[ - Our tools for firm's input choices: - .hi-blue[Choice]: combination of inputs `\((l, k)\)` - .hi-red[Production function/isoquants]: firm's technological constraints - How the *firm* trades off between inputs - .hi-green[Isocost line]: firm's total cost (for given output and input prices) - How the *market* trades off between inputs ] .pull-right[ .center[ ![](../images/management.jpg) ] ] --- # The Cost Minimization Problem: Verbally .pull-left[ - The .hi[firms's cost minimization problem]: > choose a combination of `\(l\)` and `\(k\)` to minimize total cost that produces the optimal amount of output ] .pull-right[ .center[ ![](../images/management.jpg) ] ] --- # The Cost Minimization Problem: Math .pull-left[ `$$\min_{l,k} wl+rk$$` `$$s.t. \quad q^*=f(l,k)$$` - This requires calculus to solve. We will look at **graphs** instead! ] .pull-right[ .center[ ![](../images/management.jpg) ] ] --- # The Firm's Least-Cost Input Combination: Graphically .pull-left[ - .hi[Graphical solution]: **Lowest** .hi-red[isocost line] **_tangent_ to desired** .hi-green[isoquant] (A) ] .pull-right[ <img src="2.3-slides_files/figure-html/soln-1.png" width="504" style="display: block; margin: auto;" /> ] --- # The Firm's Least-Cost Input Combination: Graphically .pull-left[ - .hi[Graphical solution]: **Lowest** .hi-red[isocost line] **_tangent_ to desired** .hi-green[isoquant] (A) - B produces same output as A, but higher cost - C is same cost as A, but does not produce desired output - D is cheaper, does not produce desired output ] .pull-right[ <img src="2.3-slides_files/figure-html/unnamed-chunk-1-1.png" width="504" style="display: block; margin: auto;" /> ] --- # The Firm's Least-Cost Input Combination: Why A? .pull-left[ .smallest[ `$$\begin{align*} \color{green}{\text{Isoquant curve slope}} &= \color{red}{\text{Isocost line slope}} \\ \end{align*}$$` ] ] .pull-right[ <img src="2.3-slides_files/figure-html/unnamed-chunk-2-1.png" width="504" style="display: block; margin: auto;" /> ] --- # The Firm's Least-Cost Input Combination: Why A? .pull-left[ .smallest[ `$$\begin{align*} \color{green}{\text{Isoquant curve slope}} &= \color{red}{\text{Isocost line slope}} \\ \color{green}{MRTS_{l,k}} &= \color{red}{\frac{w}{r}} \\ \color{green}{\frac{MP_l}{MP_k}} &= \color{red}{\frac{w}{r}} \\ \color{green}{0.5} &= \color{red}{0.5 } \\\end{align*}$$` - .hi-green[Marginal benefit] = .hi-red[Marginal cost] - .hi-green[Firm] would exchange at same rate as .hi-red[market] - .hi-purple[No other combination of (l,k) exists at current prices & output that could produce `\\(q^\star\\)` at lower cost!] ] ] .pull-right[ <img src="2.3-slides_files/figure-html/unnamed-chunk-3-1.png" width="504" style="display: block; margin: auto;" /> ] --- # Two Equivalent Rules .pull-left[ ## Rule 1 `$$\frac{MP_l}{MP_k} = \frac{w}{r}$$` - Easier for calculation (slopes) ] .pull-right[ <img src="2.3-slides_files/figure-html/unnamed-chunk-4-1.png" width="504" style="display: block; margin: auto;" /> ] --- # Two Equivalent Rules .pull-left[ ## Rule 1 `$$\frac{MP_l}{MP_k} = \frac{w}{r}$$` - Easier for calculation (slopes) ## Rule 2 `$$\frac{MP_l}{w} = \frac{MP_k}{r}$$` - Easier for intuition (next slide) ] .pull-right[ <img src="2.3-slides_files/figure-html/unnamed-chunk-5-1.png" width="504" style="display: block; margin: auto;" /> ] --- # The Equimarginal Rule Again I `$$\frac{MP_l}{w} = \frac{MP_k}{r} = \cdots = \frac{MP_n}{p_n}$$` - .hi[Equimarginal Rule]: the cost of production is minimized where the **marginal product per dollar spent** is **equalized** across all `\(n\)` possible inputs - Firm will always choose an option that gives higher marginal product (e.g. if `\(MP_l > MP_k)\)` - But each option has a different cost, so we weight each option by its price, hence `\(\frac{MP_n}{p_n}\)` --- # The Equimarginal Rule Again II .pull-left[ - Any .hi[optimum] in economics: no better alternatives exist under current constraints - No possible change in your inputs to produce `\(q^*\)` that would lower cost ] .pull-right[ .center[ ![:scale 100%](https://www.dropbox.com/s/qvr240t5j6t3arm/optimize.jpeg?raw=1) ] ] --- # The Firm's Least-Cost Input Combination: Example .bg-washed-green.b--dark-green.ba.bw2.br3.shadow-5.ph4.mt5[ .smallest[ .green[**Example**]: Your firm can use labor l and capital k to produce output according to the production function: `$$q=2lk$$` The marginal products are: `$$\begin{align*} MP_l&=2k\\ MP_k&=2l\\\end{align*}$$` ] ] .smallest[ You want to produce 100 units, the price of labor is $10, and the price of capital is $5. 1. What is the least-cost combination of labor and capital that produces 100 units of output? 2. How much does this combination cost? ] --- class: inverse, center, middle # Returns to Scale --- # Returns to Scale .pull-left[ .quitesmall[ - The .hi[returns to scale] of production: change in output when **all** inputs are increased .hi-turquoise[at the same rate] (scale) ] ] .pull-right[ ![](../images/scaleup.png) ] --- # Returns to Scale .pull-left[ .quitesmall[ - The .hi[returns to scale] of production: change in output when **all** inputs are increased .hi-turquoise[at the same rate] (scale) - .hi-purple[Constant returns to scale]: output increases at .hi-turquoise[same proportionate rate] to inputs change - e.g. double all inputs, output doubles ] ] .pull-right[ ![](../images/scaleup.png) ] --- # Returns to Scale .pull-left[ .quitesmall[ - The .hi[returns to scale] of production: change in output when **all** inputs are increased .hi-turquoise[at the same rate] (scale) - .hi-purple[Constant returns to scale]: output increases at .hi-turquoise[same proportionate rate] to inputs change - e.g. double all inputs, output doubles - .hi-purple[Increasing returns to scale]: output increases .hi-turquoise[more than proportionately] to inputs change - e.g. double all inputs, output *more than* doubles ] ] .pull-right[ ![](../images/scaleup.png) ] --- # Returns to Scale .pull-left[ .quitesmall[ - The .hi[returns to scale] of production: change in output when **all** inputs are increased .hi-turquoise[at the same rate] (scale) - .hi-purple[Constant returns to scale]: output increases at .hi-turquoise[same proportionate rate] to inputs change - e.g. double all inputs, output doubles - .hi-purple[Increasing returns to scale]: output increases .hi-turquoise[more than proportionately] to inputs change<sup>.magenta[†]</sup> - e.g. double all inputs, output *more than* doubles - .hi-purple[Decreasing returns to scale]: output increases .hi-turquoise[less than proportionately] to inputs change - e.g. double all inputs, output *less than* doubles ] ] .pull-right[ ![](../images/scaleup.png) ] .footnote[<sup>.magenta[†]</sup> See my new newsletter [Increasing Returns](https://increasingreturns.substack.com) for more on the importance of this idea ] --- # Returns to Scale: Example .bg-washed-green.b--dark-green.ba.bw2.br3.shadow-5.ph4.mt5[ .green[**Example**:] Do the following production functions exhibit *constant* returns to scale, *increasing* returns to scale, or *decreasing* returns to scale? ] 1. `\(q=4l+2k\)` 2. `\(q=2lk\)` 3. `\(q=2l^{0.3}k^{0.3}\)` --- # Returns to Scale: Cobb-Douglas .pull-left[ .smallest[ - One reason Cobb-Douglas functions are great: easy to determine returns to scale: `$$q=Ak^\alpha l^\beta$$` - `\(\alpha + \beta = 1\)`: constant returns to scale - `\(\alpha + \beta >1\)`: increasing returns to scale - `\(\alpha + \beta <1\)`: decreasing returns to scale - Note this trick *only* works for Cobb-Douglas functions! ] ] .pull-right[ ![](../images/scaleup.png) ] --- # Cobb-Douglas: Constant Returns Case .pull-left[ .smallest[ - A common case of Cobb-Douglas is often written as: `$$q=Ak^\alpha l^{1-\alpha}$$` (i.e., the exponents sum to 1, constant returns) - `\(\alpha\)` is the .hi-purple[output elasticity of capital] - A 1% increase in `\(k\)` leads to an `\(\alpha\)`% increase in `\(q\)` - `\(1-\alpha\)` is the .hi-purple[output elasticity of labor] - A 1% increase in `\(l\)` leads to a `\((1-\alpha)\)`% increase in `\(q\)` ] ] .pull-right[ ![](../images/scaleup.png) ] --- # Output-Expansion Paths & Cost Curves .center[ ![](https://www.dropbox.com/s/0lccry50i7x8shl/outputexpansion.png?raw=1) Goolsbee et. al (2011: 246) ] .smallest[ - **Output Expansion Path**: curve illustrating the changes in the optimal mix of inputs and the total cost to produce an increasing amount of output - **Total Cost curve**: curve showing the total cost of producing different amounts of output (next class) - See next class' notes page to see how we go from our least-cost combinations over a range of outputs to derive a total cost function ]